The radius of curvature of a concave mirror is 10 cm .If an object is placed in front of the mirror at a distance of 20 cm away from the mirror,find the position of the image, it's size and nature?
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We know,
f=r/2
f=10/2
=5cm
by sign convention
f= -5, 1/f= 1/-5
u= -20cm , 1/u=1/-20
by mirror formula
1/f=1/v+1/u
1/v=1/-5 -1/-20
1/v=-3/20
v=20/-3
v=-6.6 cm.
now,
m= -v/u
m= -(-6.6)/-20
m=-0.33
image formed is real,inverted and diminished .
f=r/2
f=10/2
=5cm
by sign convention
f= -5, 1/f= 1/-5
u= -20cm , 1/u=1/-20
by mirror formula
1/f=1/v+1/u
1/v=1/-5 -1/-20
1/v=-3/20
v=20/-3
v=-6.6 cm.
now,
m= -v/u
m= -(-6.6)/-20
m=-0.33
image formed is real,inverted and diminished .
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