Question

The radius of curvature of a concave mirror is 32cm and the object is placed at a distance of 20cm calculate (1)the image distance (2)focal length (3)the nature of the image formed​

Answer 1

Answer:

Radius of curvature, R=+32 cm

We know, focal length, f=

2

R

=

2

32

cm=16 cm

Thus, focal length of convex mirror, f=16 cm

Answer 2

Explanation:

Radius of Curvature R = 32 cm

Object Distance u = 20 cm

Image Distance v =

Focal length =

Nature of image =

Focal length = 32/2 = 16 cm

Since 1/v + 1/u = 1/f

1/v = 1/f - 1/u

= 1/16 - 1 / 20 = 1/16 + 1/20 ( Lcm of 20, 16 is 80)

= 5+4/80

= 9/80

= 8.8

m = h'/h = v/u

= 8.8/20

= 2.27

• Image Distance is erect
• Focal length is 16
• Nature of Image is Virtual
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