the radius of curvature of a convex mirror is 20 CM the size of the image formed is half of the size of the object find the distance of the object and image
Answers
Answered by
32
Radius of curvature = 20cm
so, focal length = 10cm
We are given, ho/2 = hi
so, ho= 2hi
so, m = hi/ho
m = ho/2ho
m = 1/2
so, m = -v/u
1/2 = -v/u
so, u = -2v
By mirror formula,
1/f = 1/v+1/u
1/10 = 1/v -(-1/2v)
1/10 = 1/v+1/2v
so, 1/10 = 2+1/2v
so, 1/10 = 3/2v
so, 2v = 30
so, v = 15 cm
so, position of object, u = -2(v) = -30
so, focal length = 10cm
We are given, ho/2 = hi
so, ho= 2hi
so, m = hi/ho
m = ho/2ho
m = 1/2
so, m = -v/u
1/2 = -v/u
so, u = -2v
By mirror formula,
1/f = 1/v+1/u
1/10 = 1/v -(-1/2v)
1/10 = 1/v+1/2v
so, 1/10 = 2+1/2v
so, 1/10 = 3/2v
so, 2v = 30
so, v = 15 cm
so, position of object, u = -2(v) = -30
Answered by
4
Answer:
I hope it helps
Explanation:
Radius of curvature = 20cm
so, focal length = 10cm
We are given, ho/2 = hi
so, ho= 2hi
so, m = hi/ho
m = ho/2ho
m = 1/2
so, m = -v/u
1/2 = -v/u
so, u = -2v
By mirror formula,
1/f = 1/v+1/u
1/10 = 1/v -(-1/2v)
1/10 = 1/v+1/2v
so, 1/10 = 2+1/2v
so, 1/10 = 3/2v
so, 2v = 30
so, v = 15 cm
so, position of object, u = -2(v) = -30
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