Question

The radius of earth is 6400km. the value of g will be 60% at the height of?​

Answer 1

✨ Answer✨

We know that acceleration due to gravity from the surface of Earth at height "h" is

given as, g' = g [1-2h/R]

(1) where h is the height from the surface of

Earth

The radius of the Earth = R = 6400 km. We have to calculate the height from the surface of the earth at which the value of g is reduced by 36% from the value at the

surface of Earth. i-e, g' = 36% of g

(2)

Comparing equations () and (), we get:

36% of g = g [1-2h/R]

(36/100) g = g [1- 2h/R]

0.36 12h/R 2h/R = 10.36

2h/R = 0.64

2h = (0.64) x R

h = (0.64)/2 x R

h = 0.32 x R

h = 0.32 x 6400

h = 2048 km

which is the required height at which the value of "g" is 36% from the value at the surface of Earth.

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