The radius of gyration of a ring about the tangent perpendicular to its plane is ______.
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The moment of inertia of a uniform circular disk about the centroidal axis in the plane of the disk is:
IC=14mR2IC=14mR2
Use the parallel axis theorem to determine the moment of inertia about a line tangent to the disk:
IY=IC+md2IY=IC+md2
where d= perpendicular distance from the tangent line to the centroidal axis
therefore, d=R
IY=IC+mR2IY=IC+mR2
or
IY=14mR2+mR2=54mR2IY=14mR2+mR2=54mR2
The radius of gyration k=Im−−√k=Im
or
k=(54)mR2m−−−−−−√k=(54)mR2m=5R24−−−√5R24
or
k=5√2R
finally it may be 1.414*radius of ring
IC=14mR2IC=14mR2
Use the parallel axis theorem to determine the moment of inertia about a line tangent to the disk:
IY=IC+md2IY=IC+md2
where d= perpendicular distance from the tangent line to the centroidal axis
therefore, d=R
IY=IC+mR2IY=IC+mR2
or
IY=14mR2+mR2=54mR2IY=14mR2+mR2=54mR2
The radius of gyration k=Im−−√k=Im
or
k=(54)mR2m−−−−−−√k=(54)mR2m=5R24−−−√5R24
or
k=5√2R
finally it may be 1.414*radius of ring
adityasolanke1432:
I want in terms of 2 and R
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here is your answer dude
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