Question

The radius of gyration of a rod of maa 100g and length 100cm about an axis passing through the centre of gravity and perpendicular to its length

Answer 1

Hola User_____________________

Here is Your Answer...!!!
____________________________

⭐Actually welcome to the concept of the ROTATIONAL DYNAMICS...

⭐Basically after solving we get this....
for here the

⭐MOMENT OF INERTIA OF A ROD THROUGH ITS CENTRAL AXIS IS given by

⭐I = ML^2/12

⭐Since Radius of Gyration is given by

⭐I = MK^2

⭐so..

⭐K = Underoot I/M

______________________________

Hope it helps u.....☺

Answer 2

Hola User_____________________

Here is Your Answer...!!!

____________________________

⭐Actually welcome to the concept of the ROTATIONAL DYNAMICS...

⭐Basically after solving we get this....

for here the

⭐MOMENT OF INERTIA OF A ROD THROUGH ITS CENTRAL AXIS IS given by

⭐I = ML^2/12

⭐Since Radius of Gyration is given by

⭐I = MK^2

⭐so..

⭐K = Underoot I/M

______________________________

Hope it helps u.....☺