The radius of one circular field is 20m and that of another field is 48m. Find the radius of the third circular field whose area is equal to the sum of the areas of the other two field
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πr^2 + πR^2 = to the area of the third circle
22/7*20*20 + 22/7*48*48 = area of the third circle
area of the third circle= 8498.28sq.m
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