Question

The radius of roller is 56 cm and its length is 125cm. Find the area levelled by the roller
in one revolution. Also find the area of the playground levelled by this roller in 250
revolutions.

Answer 1

Answer:

Given that,

radius=56cm

length=125 cm

asking that what's area of playground in revolution and 250revolution ?

Lateral surface area of rollers=2πrh

2*22/7*56*125=44000cm^2

area of playground in one revolution=44000cm^*1

=44000cm^2

we will it into m^2

44000/100*100=4.4m^2

area in 250 revolution=4.4m^2*250 = 1100m^2

IF YOU UNDERSTAND THIS SOLUTION THEN GIVE SOME FEEDBACK

Answer 2

Answer:

best answer as it was very much helpful to me and in second time I did it correctly