Question

The radius of second orbit of an electron in hydrogen atom is 2.116 . The de-broglie wavelength associated with this electron in this orbit would be:

Answer 1

Answer:

Answer:

Debrogile wave length =h/MV(h=6.6×10*-34)(me=9.1×10*-31) velocity is(2.18×10*6)

Explanation:

=6.6×10*-34/9.1×10*-31×2.18×10*6=3.33×10*-10