Question

The radius of the base of a cylinder is 2.1 cm and height 5 cm, then its volume is​

Answer 1

$\bigstar \: \frak{Diagram}$

$\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{2.1 \: cm}}\put(9,17.5){\sf{5 \: cm}}\end{picture}$

$\bigstar \: \frak{Required \: Solution }$

$\text{\red{Given:-}}$

• Radius of cylinder = 2.1 cm

• Height of cylinder = 5cm

$\text{\pink{To find:-}}$

• Volume of Cylinder

We know

$\bigstar \boxed{ \rm{Volume \: of \: cylinder = \pi {r}^{2}h }}$

By using this formula we can find value of volume of Cylinder

$\dashrightarrow\sf Volume \: of \: cylinder = \pi {r}^{2}h$

$\dashrightarrow\sf Volume \: of \: cylinder = \dfrac{22}{7} \times {(2.1)}^{2} \times 5$

$\dashrightarrow\sf Volume \: of \: cylinder = \dfrac{22}{7} \times 2.1 \times 2.1 \times 5$

$\dashrightarrow\sf Volume \: of \: cylinder = \dfrac{22}{7} \times \dfrac{21}{10} \times \dfrac{21}{10} \times 5$

$\dashrightarrow\sf Volume \: of \: cylinder = \dfrac{22}{\cancel7} \times \dfrac{\cancel{21}}{10} \times \dfrac{21}{\cancel{10}} \times \cancel5$

$\dashrightarrow\sf Volume \: of \: cylinder = \dfrac{22}{1} \times \dfrac{3}{10} \times \dfrac{21}{2} \times 1$

$\dashrightarrow\sf Volume \: of \: cylinder = \dfrac{\cancel{22}}{1} \times \dfrac{3}{10} \times \dfrac{21}{\cancel2} \times 1$

$\dashrightarrow\sf Volume \: of \: cylinder = \dfrac{11}{1} \times \dfrac{3}{10} \times \dfrac{21}{1} \times 1$

$\dashrightarrow\sf Volume \: of \: cylinder = \dfrac{33 \times 21}{10}$

$\dashrightarrow\sf Volume \: of \: cylinder = \dfrac{693}{10}$

$\dashrightarrow \underline{ \boxed{\sf Volume \: of \: cylinder = 69.3 \: cm}}$

$\therefore \: \underline{ \sf Volume \: of \: cylinder = \bf69.3 \: cm}$

$\bigstar \: \frak{Know~more}$

$\boxed{\begin{minipage}{6.2 cm}\bigstar \:\underline{\textbf{Formulae Related to Cylinder :}}\\\\\sf {\textcircled{\footnotesize\textsf{1}}} \:Area\:of\:Base\:and\:top =\pi r^2 \\\\ \sf {\textcircled{\footnotesize\textsf{2}}} \:\:Curved \: Surface \: Area =2 \pi rh\\\\\sf{\textcircled{\footnotesize\textsf{3}}} \:\:Total \: Surface \: Area = 2 \pi r(h + r)\\ \\{\textcircled{\footnotesize\textsf{4}}} \: \:Volume=\pi r^2h\end{minipage}}$