The radius of the base of a right circular cylinder is halved and the height is double. what is the ratio of the volume of the new cylinder to that of the original cylinder
Answers
Answered by
27
hello users .....
we have given that :
radius of the base of a right circular cylinder is halved and the height is double .
we have to find :
ratio of the volume of the new cylinder to that of the original cylinder.
solution:-
let for original cylinder
the radius of the cylinder = r
and
height = h
we know that :
volume of cylinder = πr²h
according to question :
the radius of new cylinder = r/2
and
height = 2h
now,
volume of original cylinder
= πr²h
&
volume of New cylinder
= π(r/2)²(2h)
= 2πr²h / 4
=> πr²h / 2
now,
Ratio between their volumes
= ( πr²h/2) / ( πr²h)
=> 1/2
hence ,
their volumes are in ratio of 1:2 answer
⭐⭐ hope it helps ⭐⭐
we have given that :
radius of the base of a right circular cylinder is halved and the height is double .
we have to find :
ratio of the volume of the new cylinder to that of the original cylinder.
solution:-
let for original cylinder
the radius of the cylinder = r
and
height = h
we know that :
volume of cylinder = πr²h
according to question :
the radius of new cylinder = r/2
and
height = 2h
now,
volume of original cylinder
= πr²h
&
volume of New cylinder
= π(r/2)²(2h)
= 2πr²h / 4
=> πr²h / 2
now,
Ratio between their volumes
= ( πr²h/2) / ( πr²h)
=> 1/2
hence ,
their volumes are in ratio of 1:2 answer
⭐⭐ hope it helps ⭐⭐
Answered by
12
I hope it will help u
Attachments:
Similar questions
English,
8 months ago
Computer Science,
8 months ago
Math,
8 months ago
English,
1 year ago
Math,
1 year ago
Chemistry,
1 year ago
Social Sciences,
1 year ago