The radius of the base of a right circular cylinder is increased by 75% and the height is
decreased by 50%. Find the per cent increase or decrease in the volume
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Answer:
right cicular cylinder is increased by 75%and the hight is cicular
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Step-by-step explanation:
Let initial radius be, r
Then, new radius = r(100+75/100) = 7r/4
New height = h(100-50/100) = h/2
initial volume = pie r^2h
new volume= pie(7r/4)^2 (h/2) = 49/32 pie r^2h
therefore, percentage increase= new volume - initial volume/initial volume *100
After substitution = 49/32pie r^2h- pier^2h/pier^2h *100
= (49/32 - 1) pie r^2h/ pie r^2h *100
= (49/32-1) 100=17/32*100=425/8= 53.12 %
therefore, the percentage increase in volume of the cylinder is 53.12%
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