The radius of the bohr orbit in the ground state of hydrogen atom is 0.5 å. the radius of the orbit of the electron in the third excited state of he+ will be
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r4 = 4 å.
Explanation:
Given: The radius of the bohr orbit in the ground state of hydrogen atom is 0.5 å.
Find: The radius of the orbit of the electron in the third excited state of he+.
Solution:
The radius of the orbit of the electron in nth excited state can be found using the formula:
rn = ro n² /Z
where ro is the radius of the Bohr orbit in the ground state atom.
So for He+ third excited state n = 4, Z = 2, and ro = 0.5 å.
Hence r4 = 0.5 * 4² / 2 = 4 å.
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