the radius of the circle and 19 cm and 9 cm find the radius of a circle which has a circumference equal to the sum of the two circumference
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Answered by
4
let the radius of the required cicle ber cm
so 2×22/7 ×r =2×22/7(19+9)
or r=28 (ans)
so 2×22/7 ×r =2×22/7(19+9)
or r=28 (ans)
nikhilAwasthi:
i think you r in correct
Answered by
11
Hi !
Radius of bigger circle = 19 cm = R
Radius of smaller circle = 9 cm = r
Circumference of bigger circle + Circumference of smaller circle = circumference of new circle
Let the radius of the new circle be R'
so ,
2πR + 2πr = 2πR'
2π × (R + r) = 2π × R'
2π gets cancelled on both sides,
R + r = R'
19 + 9 = R'
28 = R'
Hence,
Radius of new circle = R' = 28 cm
Hope this helps you !
Radius of bigger circle = 19 cm = R
Radius of smaller circle = 9 cm = r
Circumference of bigger circle + Circumference of smaller circle = circumference of new circle
Let the radius of the new circle be R'
so ,
2πR + 2πr = 2πR'
2π × (R + r) = 2π × R'
2π gets cancelled on both sides,
R + r = R'
19 + 9 = R'
28 = R'
Hence,
Radius of new circle = R' = 28 cm
Hope this helps you !
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