The radius of the circle is 25m and
the length of one of its chood is 40cm
find the distance of the chord from
the Centre ?
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Answer:
by Pythagoras theorem
we know that
H^2=B^2+H^2
Step-by-step explanation:
so
ATC
25^2=20^2+H^2
H^2=25*25-20*20
H^2=625-400
H^2=225
H=✓225
H=15
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