The total surface area and volume of a rectangular parallelopiped be 192 cm- and 144 cm respectively.
If the length of the diagonal be 13 cm, then find the three dimensions of the rectangular parallelopiped.
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Volume of rectangular parallel pipe = l * b * h = 144 cm …………… (1)
Surface Area = 2( lb + bh + hl ) = 192 cm²
Corner to corner diagonal = 13 cm
l² + b² + h² = 13² = 169
Since, ( l + b + h )² = l² + b² + h² + 2( lb + bh + hl )
=> ( l+ b+ h)² = 169 + 192 = 361
=> l + b + h = 19 …………… (2)
By ( 1) & (2)
l b h = 144
& l + b + h = 19
Now, since prime factors of 144 =2 x 2 x 2 x 2 x 3 x 3
Since 19 = 1+18
19 = 2+ 17
19 = 3 + 16
Or, 19 = 3 + 12 + 4 , we select 12 & 4 as 3,12,& 4 contain all the prime factors of 144
=> l x b x h = 12 x 4 x 3 = 144
& l + b + h = 12 + 4 + 3 = 19
Therefore, 3 sides.. length = 12cm
breadth = 4 cm
height = 3cm
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