Question

the radius of the circle is 5cm and the distance of the chord from the centre of the circle is 4cm then the length of the chord is
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Answer 1

So, seg AM = seg MB (Perpendicular drawn from the centre to a chord bisects the chord)

By using Pythagoras theorem, in right triangle AOM,

AM2 + OM2 = OA2

⇒ AM2 + 42 = 52

⇒ AM2 +16 = 25

⇒ AM2 = 25 – 16

⇒ AM2 = 9

⇒ AM = 3 cm

But seg AM = seg MB = 3 cm

∴ Seg AB = seg AM + seg MB = 3 cm + 3 cm = 6 cm

Therefore, the length of the chord is 6 cm.

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