the radius of the circle with center P is 25 cm the length of a chord of a circle is 48cn find the distanc of the chord form the center P of the circle
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Answer:
7cm
Step-by-step explanation:
Let the centre be P.
Let the chord be AB.
Let the chord meet AB at O.
∠POB=90° because line drawn from centre to the chord of circle makes right angles with it. (theorem)
OB=AO=48/2=24cm
Join BP.
Using pythagoras theorem,
h²=p²+b²
25²=24²+OP²
625=576+OP²
OB²=49
OB=7cm
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