Question

The radius of the circumcircle of a right angled triangle is 3cm and the altitude drawn to the hypotenuse is 2cm long.find the sum of the areas of the three disjoint segments of this circumcircle formed by the sides of this triangle

Answer 1

Answer:

The areas of the three disjoint segments will be 22.26 cm²

Step-by-step explanation:

Given radius of the circumcircle = 3 cm

=> area of the circumcircle = πr² = 3.14 x 9 = 28.26 cm²

In a circumcircle of a right angled triangle, the hypotenuse is the diameter of the circle,

radius = 3 cm

=> diameter = hypotenuse = 2 x 3 = 6 cm

Altitude drawn to the hypotenuse = 2 cm

So area of the triangle = 1/2 x base x height

= 1/2 x 6 x 2

= 6 cm

Hence

Area of the disjoint segments = Area of circumcircle - area of triangle

= 28.26 - 6

= 22.26 cm²

Hence the areas of the three disjoint segments will be 22.26 cm²

Answer 2

Answer:

area of disjoint segments= 22.26cm sq.

Step-by-step explanation:

take the help from the above picture.