Question

The radius of the cylinder is doubled whose lateral surface area is unchanged the height will be

Answer 1

Let r be the original radius of cylinder & h be the height of the cylinder
Then, Lateral Surface Area = a = 2pi×r×h

Let doubled radius be R & changed height be H
Now, LSA= 2pi×R×H

Since LSA remains unchanged,
2pi×r×h = 2pi×R×H - - - - - - - - - - - - (1)
Since R=2r - - - - - - (Radius has been doubled)

Hence equation (1) becomes,
2pi×r×h = 2pi×2r×H
r×h=2r×H
h=2×H
H=h/2

Hence new height of the cylinder is now half the original height.

Answer is,
The radius of the cylinder is doubled whose lateral surface area is unchanged, the height will be __halved_

Answer 2

Answer:

Option C

Step-by-step explanation:

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