Question

THE RADIUS OF THE FIRST ORBIT IS OPTIONS a) 0.529A° b) 0.0529 c) 52.9pm d) 529 m
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Answer 1

Answer:

Let us consider the nth bohr orbit,

rn=4π2mZe2n2h2

For hydrogen atom z=1, first orbit n=1

r1=4πr2me2h2=0.592A0

(i)For He+ion,Z=2,thirdorbit,n=3

r3(He+)=4π2m×2×e232h2

=29[4π2me2h2]

=29×0.592

=2.380A0

(ii) For Li2+ion,Z=3,

secondorbitn=2

r2(Li2+)=4π2m×3×e222h2

=34[4π2me2h2]

      = 0.705A0