The radius of the sphere is measured 2.1 ± 0.5 cm. Calculate its surface area along with error limits. Give the answer in description. Any kind of faislami will be reported .
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surface area of sphere
A=4πr2
a=4×3.14×(2.1)2
=55.4cm2
A=4πr2
A=4×3.14×(2.1)2
=55.4cm2\\ AΔA=2×rΔr
ΔA=2×rΔr×A
=2×2.10.5×55.4
=26.4cm2
Surface area =(55.4±26.4)cm2
Answered by
1
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surface area of sphere
A=4πr 2
a=4×3.14×(2.1) 2 =55.4cm 2
A=4πr 2
=4×3.14×(2.1)
=55.4cml2 \\ AΔ
=2× rΔrΔA
=2× rΔrl ×A =2× 2.10. ×55.4=26.4cm 2
Surface area =(55.4±26.4)cm 2
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