the radius of two circles are in the ratio 5 is to 8 if the difference between the area is 351 pi square cm .
.find the area of the bigger circle .( take pi as 3.14)
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Answered by
22
Hi
Let the common factor be x.
Therefore, the radius of both the circles becomes 5x and 8x respectively.
Area of the first circle
= 22/7 * 5x *5x
=(22 * 25 x^2) /7
Area of the the other circle
= 22/7 *8x*8x
=( 22*64x^2) /7
By the problem,
22 x^2 (64- 25) =351 *22/7 *1/7
=> x^2 = 351cm^2/39
=>x^2 = 117cm^2/13
=>x^2 =9cm^2
=>x = 3 cm
Therefore, the radius of the first circle
=5 *3cm
= 15cm
The radius of the second circle
=8*3cm
= 24 cm
Hope this is of help.
Let the common factor be x.
Therefore, the radius of both the circles becomes 5x and 8x respectively.
Area of the first circle
= 22/7 * 5x *5x
=(22 * 25 x^2) /7
Area of the the other circle
= 22/7 *8x*8x
=( 22*64x^2) /7
By the problem,
22 x^2 (64- 25) =351 *22/7 *1/7
=> x^2 = 351cm^2/39
=>x^2 = 117cm^2/13
=>x^2 =9cm^2
=>x = 3 cm
Therefore, the radius of the first circle
=5 *3cm
= 15cm
The radius of the second circle
=8*3cm
= 24 cm
Hope this is of help.
Answered by
3
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