prove that √x is not a rational number if x is not perfect square
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Let us suppose that √5 is a rational number.
So √5 = p/q
=> 5 = p2 /q2
=>5q2 = p2 ..............1
So p2 is divisible by 5
=> p is divisible by 5
Let p =5x (x is a positive integer)
Now p2 = 25c2
from equation 1
5q2 = 25c2
=> q2 = 5c2
So q is divisible by 5
Thus p and q has a common factor 5. It is contradiction of our assumption.
So, √5 is not a rational number.
use x in the place of 5
So √5 = p/q
=> 5 = p2 /q2
=>5q2 = p2 ..............1
So p2 is divisible by 5
=> p is divisible by 5
Let p =5x (x is a positive integer)
Now p2 = 25c2
from equation 1
5q2 = 25c2
=> q2 = 5c2
So q is divisible by 5
Thus p and q has a common factor 5. It is contradiction of our assumption.
So, √5 is not a rational number.
use x in the place of 5
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bye
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