the raito of the 5th and 3rd term of an AP is 2:5 find the ratio of 15th and 7th term.
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hrya
now, a5a3 = 25⇒(a + 4d)(a + 2d)= 25⇒5a + 20d = 2a + 4d⇒3a = −16d⇒a = − 163d ......(1)now, a15a7 = a + 14da + 6d = − 163d + 14d−163d + 6d = 263d23d= 131
(a+4d)/(a+2d) =2/5
(a+4d+a+2d)/(a+4d- a-2d) = (2+5)/(2-5)
-3a = 16d
d = -3a/16
15th term / 7th term = a+14d)/(a+6d)
put d = -3a/16 and get ratio
now, a5a3 = 25⇒(a + 4d)(a + 2d)= 25⇒5a + 20d = 2a + 4d⇒3a = −16d⇒a = − 163d ......(1)now, a15a7 = a + 14da + 6d = − 163d + 14d−163d + 6d = 263d23d= 131
(a+4d)/(a+2d) =2/5
(a+4d+a+2d)/(a+4d- a-2d) = (2+5)/(2-5)
-3a = 16d
d = -3a/16
15th term / 7th term = a+14d)/(a+6d)
put d = -3a/16 and get ratio
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