The range of a projectile fired at an angle of 15° is 50m.
Answers
Answered by
4
In FIRST CASE range =50 =u²/g(sin2 x 15°)
=u²/2g
u²/g=100
In second case range =u²/g (sin 2 x 45°)
=[u²/g ]sin90=100m
Answer: 100m
=u²/2g
u²/g=100
In second case range =u²/g (sin 2 x 45°)
=[u²/g ]sin90=100m
Answer: 100m
Similar questions