Math, asked by Asheem11, 7 months ago

The range of the fonction f(x) = cosec^2(x).+ sec^x is​

Answers

Answered by abu971
0

Answer:

ANSWER

LHS :

3

cosec20

o

−sec

2

20

o

=

sin20

o

3

cos20

o

1

=

sin20

o

cos20

o

3

cos20

o

−sin20

o

=

sin20

o

cos20

o

2[

2

3

cos20

o

2

1

sin20

o

]

=

sin20

o

cos20

o

2(sin60

o

cos20

o

−cos60

o

sin20

o

)

=

sin20

o

cos20

o

2sin(60

o

−20

o

)

=

sin20

o

cos20

o

2sin40

o

=

2sin20

o

cos20

o

4sin40

o

=

sin40

o

4sin40

o

=4 = RHS

Step-by-step explanation:

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