The rate constant for a first order decomposition of H2O2 is given by the following equation log K=14.2-(1.0x104 )K / T. Calculate activation energy and rate constant K if its half life period be 200 minutes
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log k = 14.2-(10^4)k/t...? have 10^4... if yes than log k= logA- E/ 2.303RT... compare both equation than - 10^4*1/t = E/2.303 Rt...than E = 191.47 kJ/mol
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