Question

The rate constant for a reaction at 500°C is 1.6 x 10³ M⁻¹ s⁻¹. What is the frequency factor of the reaction if its energy of activation is 56 kJ mol⁻¹.

Answer 1

The formula,

Ki = A * e^-E/RT is used for the analyses,

Here we have the value of the rate constant and temperature that is 1.6 * 10^3 at 500 degrees C.

Also, the activation number if given to us.

Hence, we can calculate A that is the correlating collision frequency.