Question

The rate constant k, of a reaction is found to be
double that of rate constant k, of another reaction.
The relationship between corresponding activation
energies of the two reactions at same temperature
(E, & E.) can be represented as
(1) E1 > E2
(2) E1 <E2
(3) E1 = E2
(4) E1 = 4E2
​

Answer 1

Thus, when the activation energy increases, the rate constant of the reaction decreases. The rate constant (K1) of one reaction is found to be double that of the rate constant of (K2) of another reaction. Hence, its activation energy is less than that of the second reaction E1<E2.