The rate constant of a certain first order reaction is 3.12 x 10-3. Min-!: (a) how many minutes does it take for the reactant concentration to drop to 0.02 m if the initial concentration of the reactant is 0.045 m
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Answer:
Given, K=6.8×10
−4
s
−1
; [A
o
]=0.04 M;
t=20 min=20×60=1200 sec
K=
t
2.303
log
[A
t
]
1
[A]
o
⟹6.8×10
−4
=
1200
2.303
log
10
(
[A
t
]
0.04
)
⟹Antiog(0.3545)=
[A
t
]
0.04
⟹2.261=
[A
t
]
0.04
⟹[A
t
]=0.0177 M
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