the rate constant of a reaction is 2.4×10^-3 at 300k temperature its value becomes four times by increase in temperature by 60°C then what will be its rate constant at 330k temperature
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Answer:
Using Arrheneius equation we get
lnk=−
RT
E
a
ln(
k
2
k
1
)=
R
E
a
(
T
2
1
−
T
1
1
)
on substitution we get:
ln(
3×5×10
−4
5×10
−4
)=
1.987
E
a
(
320
1
−
300
1
)
E
a
=10478.12 cal/mol
Rate constant at 37
∘
C T=310 K
lnk=−
1.987×310
10478.12
=−17.01
k=4.09×10
−8
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