Question

the rate constant of a reaction is 2.5 into 10 to the power minus 2 per minute the order of the reaction is

Answer 1

The reaction is first order, since the rate constant have units of per second

Answer 2

Answer:

The order of the reaction is  3

Explanation:

Rate $=k[\text { concentration }]^{n}$

[०]

Here, $n=$ order of Reaction

$k=$Rate constant.

So,$k=\frac{\text { Rate }}{\left[\text { conc }^{n}\right]^{n}}=\frac{\text { mol } l^{-1} \min ^{-1}}{\left(m o l l^{-1}\right)^{n}}$

Given$\rightarrow 2.5 \times 10^{-2} \mathrm{~mol}^{-2} l^{2} \mathrm{~min}^{-1}$

$\therefore{mol}^{-2} l^{2} \min ^{-1}=\frac{{mol} l^{-1} \min ^{-1}}{\left({mol} l^{-1}\right)^{n}}$

$\left(mol} l^{-1}\right)^{n}=\{mol}^{3} l^{-3} \Rightarrow\left(\{mol} L^{-1}\right)^{3}$

So,$n=3$