Question

The rate of a certain
hypothetical reaction A + B + C
products is given by r = -d[A]
dt K[A]1/2[B]1/3[C]1/4. The order
of the reaction is​

Answer 1

Answer:

The order of the given chemical reaction that has the rate expression r $=$ $\frac{-d\left[\begin{array}{ccc}A\end{array}\right] }{dt}$ $= K\left[\begin{array}{ccc}A\end{array}\right]^{\frac{1}{2} } \left[\begin{array}{ccc}B\end{array}\right]^{\frac{1}{3} }\left[\begin{array}{ccc}C\end{array}\right]^{\frac{1}{4} }$  is  $\frac{13}{12}$·

Explanation:

The given chemical reaction is $:$

                  A $+$ B $+$ C → Products

The rate expression is $:$

                  $r$ $=$  $\frac{-d}{dt} \left[\begin{array}{ccc}A\end{array}\right] = K \left[\begin{array}{ccc}A\end{array}\right]^{\frac{1}{2} }\left[\begin{array}{ccc}B\end{array}\right]^{\frac{1}{3} }\left[\begin{array}{ccc}C\end{array}\right]^{\frac{1}{4} }$

We know that,

      Order of a chemical reaction is the sum of the power of concentration of reactants in the rate expression·

∴  By adding the powers we get,

   Order of the reaction $=$   $\frac{1}{2} + \frac{1}{3} + \frac{1}{4}$

⇒  Order of the reaction $= \frac{13}{12}$