Question

The rate of a chemical reaction quadruples when the temperature is increased from 27°C to 47°C.
The activation energy of the reaction is​

Answer 1

Answer:

From Arrhenius equation, we obtain

The rate of the reaction can be written as:

ln(  K  1K 2  )=  

R

E  

a

​  

 

​  

[  

T  

1

​  

 

1

​  

−  

T  

2

​  

 

1

​  

]

ln(  

1

4

​  

)=  

8.314

E  ​  

[  300 1  −  310 1  ]

⇒E  

a =107.2 KJ/mol

October 15, 2019