Question

The rate of a reaction doubles when its temperature changes from 300k to 310k.Ea of reaction will be:(R=8.314JK−1mol−1;log 2=0.3010)

Answer 1

The rate of a reaction doubles when its temperature changes from 300k to 310k.Ea of reaction will be:(R=8.314JK−1mol−1;log 2=0.3010)?

ANSWER

∵r1r2=k1k2=2

Now 2.303log10k1k2=REa[T1T2T2−T1]

2.303log102=8.314Ea×[310×300310−300]

∴Ea=102.303×0.301×8.314×310×300=53598.6J

=53.6kJmol−1

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