Question

The rate of a reaction doubles when its temperature changes from 300 K to 310 K. Activation energy of such a reaction will be : (R = 8.314 JK⁻¹ mol⁻¹ and log 2 = 0.301)
(a) 53.6 kJ mol⁻¹
(b) 48.6 kJ mol⁻¹
(c) 58.5 kJ mol⁻¹
(d) 60.5 kJ mol⁻¹

Answer 1

a option formula is log k2/k1=Ea /2.303R {1/T1-1T2} then you find the exact ans where log k2/k1 is log2 Becaz Q's main kha hai ki rate of rexn double