Question

the rate of change of momentum of a body mass 10 kg is 5 kg ms-2 the froce acting on the body is​

Answer 1

Answer:

Given,

Mass, m=5kg

Momentum, p=10kgm/s

Force, F=0,2N

Time, t=10seconds

According to Newton’s second law,

Force = Rate of change of momentum

F=(p2−p1)/t

0.2=(mv−10)/10

Or mv–10=2

Or 5×v−10=2

Or v=12/5=2.4m/s

p2 = mv = 5 × 2.4 = 12 kg m/s

Increases in kinetic energy = (p

2

2

−p

1

2

)2m

=(12

2

−10

2

)/(2×5)=4.4J

Answer 2

Answer:

30 joules

Explanation:

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