Physics, asked by avneetaulakh200254, 5 months ago

The rate of change of momentum of a body of mass 10 kg is 5 kg m s⁻². The force acting on the body is *

(a) 2 N

(b) 5 N

(c) 6 N

(d) 50 N

​Answer- With Explain

Answers

Answered by MysticPetals
18

Given

» Rate of change of momentum , p = 5 Kg ms⁻²

» Mass of the body , m = 10 Kg

To Find

» The force acting on the body = ?

Formula

 \bf \: momentum(p) = m \times v

Where m → mass of the body

v → Velocity of the body

Here we know the values of momentum and mass , Thereby we can calculate the velocity !!

Velocity = momentum / mass

= 5 / 10 = 1 /2 m/s

Velocity of the body = 0. 5 m/s

Force = mass × acceleration

F = 10 × 9. 8 = 98 N

Usually The acceleration due to gravity be 9.8 ms⁻²

If we take Velocity as the acceleration then ,

F = 10 × 0. 5 = 5N ( b)

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