The rate of different reactions is different. Justify the statement.
Answers
Answered by
0
Answer:
t1/2= 0.693/ k is the answer I think
Answered by
1
Answer:
Consider the first order reaction ,
R→P
For this reaction , rate law which relates the rate of reaction to the concentration of reactants can be given as
Rate =
dt
−d[R]
=k[R]
For a first order reaction ,
t=
k
2.303
log
[R]
[R]
0
, where [R]
0
= initial concentration , [R]= concentration at time t.
At t
1/2
,[R]=[R]
0
/2
So , the above equation becomes
t
1/2
=
k
2.303
log
[R]
0
/2
[R]
0
t
1/2
=
k
2.303
log2 or t
1/2
=
k
2.303
×0.3010
t
1/2
=
k
0.693
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