Question

the rate of diffusion of gas A is double that of gas B the ratio of the molecular weights is

Answer 1

Answer:

THE ANSWER IS 1:4

Explanation:

rA=2rB

rA/rB=√mB/mA/mB/mA

=2/1

=4/1=mB/mA

mA/mB=1/4

=1:4

Answer 2

Given:

The rate of diffusion of gas A is double that of gas B.

To Find:

The ratio of the molecular weights.

Solution:

To find the ratio of the molecular weights will follow the following steps:

As we know,

The rate of diffusion is inversely proportional to the square root of molecular weights.

Let m1 and m2 be the molecular weight of A and B respectively.

Then,

$\frac{r1}{r2} = \sqrt{ \frac{m2}{m1} }$

According to the question putting values in the above equation-

$2 \: = \sqrt{ \frac{m2}{m1} }$

By squaring both sides we get,

$4 = \frac{m2}{m1}$

$\frac{1}{4} = \frac{m1}{m2}$

Henceforth, the ratio of the molecular weights is 1/4.