Question

the rate of first order reaction is 0.04 mol /l/s at 10 seconds and 0.03 at 20 second after initiation of the reaction. the half life period of this reaction is​

Answer 1

U have to just put the values into the formulae for the first order eqn. that is:

K = (2.303/t2 – t1)log(Q1/Q2)

=(2.303/(10)llog(0.04/0.03)

After solving,

K = 0.02876 /min

thalf = 0.693/k = > 24 min approx