The rate of flow of liquid through a capillary tube under
a constant pressure head is Q. If radius of tube is
reduced to half and length is made three times, the
new rate of flow of liquid under same pressure head is
a)Q/24
b)Q/36
c)Q/48
d)Q/64
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Answer:
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Explanation:
Q/32
Theflowthroughthepipeisgivenby,
Q=
8ηL
ΔPπR
4
NowR
‵
=
2
R
,L
‵
=2L
KeepingallotherfactorsconstantandsubstitutingforRandL,
Q
‵
=
8η
ΔPπ
(
2L
16
R
4
)
Q
‵
=
8η
ΔPπ
(
32L
R
4
)
Q
‵
=
8ηL
ΔPπR
4
×
32
1
∵Q
‵
=
32
Q
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