Question

The rate of radiation of a black body at 0ºC is E joule per sec. Then the rate of radiation of this black body at 273ºc will be (a) 16 E (b) 8 E (c) 4 E (d) E

Answer 1

Answer:

hey

here is your answer

answer is (E)

Answer 2

The ratio of energy emission will be directly proportional to fourth power of temperature ratio can be found out from given data.

ΔQ

1

ΔQ

2

=

σAT

1

4

σAT

2

4

T

1

=273+273K=546K;T

2

=273K

substituting the temperature values in the Stefan's law

ΔQ

1

ΔQ

2

=

σA546

4

σA273

4

=

2

4

1

⇒ΔQ

2

=

16

ΔQ

1

Thus the correct answer is A.

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