The rate of reaction becomes double by rise of 10 temperature explain
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Why does the rate of reaction double with every 10 degree rise in temperature?
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Rudransh Sharma, Passed 12 with flying colours.
See,
Rate is dependent on rate const as the rate law expression beautifully states
Rate = rate const(k) * (conc of reaction )^order
Or in another words rate is directly proportional to rate constant
And rate constant is determined by an equation called Arrhenius eqn which states
K=A*e^-(energy of activation /(R * T))
So if u increase temp the k will increase so if u do some math by taking log and eliminating A and calculating for 2 temp 10 deg apart ull find approx double const and so will the rate be double.
Hope this helps
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