Question

the ratio between a two digit number and the sum of its digits are 4:1. if the digit at unit place in three more than digit at tenth place then the number is:​

Answer 1

Answer:

Let the ten's digit be x

Then, units digit = x + 3

Number = 10x + (x + 3)

= 11x + 3

Sum of digits = x + (x + 3)

= 2x + 3

∴11x+32x+3=41⇔11x+3=8x+12⇔3x=9⇔x=3

Hence, Required number

= 11x + 3

= 11 × 3 + 3

= 36