Question

the ratio between a two digit number and the sum of the digits of that number is 4 is to 1 if the digit in the units place is 3 more than the digit in the tens place what is the number

Answer 1

Hi ,

according to the problem given,

let the ten's place digit = x

unit place digit = x + 3

Original number = 10x + ( x+ 3 )

= 11x + 3

sum of the digits = x + x + 3

= 2x + 3

given ratio ,

( 11x + 3 ) : ( 2x + 3 ) = 4 : 1

product of the extremes = product of means

( 11x + 3 ) × 1 = 4 × ( 2x + 3 )

11x + 3 = 8x + 12

11x - 8x = 12 - 3

3x = 9

x = 9 / 3

x = 3

Therefore ,

Required number = 11x + 3

= ( 11 × 3 ) + 3

= 33 + 3

= 36

I hope this helps you.

:)