The ratio between length and breadth of a field is 10 : 6. The area of the field is 3840m². Find the difference between the length and width of the field.
Answers
The difference between the length and width of the rectangular field are 32 m.
Given :
• The ratio between length and breadth of a rectangular field is 10 : 6. The area of the rectangular field is 3840m2.
To Find :
The difference between the length and width of the rectangular field.
Solution :
Let us assume that, the length of a rectangle is 10x m and the breadth of a rectangle is 6x m respectively.
As we know that
Area of rectangle = length * breadth
=3840 = 10x * 6x
oo
= 3840 = 60x²
- x2 = 3840/60
→ x² = 384/6
- x² = 64
- x = V64
= x = 8
Therefore,
= Length of a rectangle = 10x
= Length of a rectangle = 10 * 8
» Length of a rectangle = 80m
- Breadth of a rectangle = 6x
- Breadth of a rectangle = 6 * 8 =48m.
Now,
The difference between the length and width
of the rectangular field :
Length - Breadth
80 - 48
32m.
By using the required fоrmulа, аnd substituting аll the given vаlues in the fоrmulа, we get:
→ Аreа оf seсtоr
= 60/360 × 22/7 × (7)²
→ Аreа оf seсtоr
= 6/36 × 22/7 × 7 × 7
→ Аreа оf seсtоr
= 1/6 × 22/7 × 7 × 7
→ Аreа оf seсtоr
= 1/6 × 22 × 7
→ Аreа оf seсtоr
= 1/3 × 11 × 7
→ Аreа оf seсtоr
= 1/3 × 77
→ Аreа оf seсtоr
= 77/3
→ Аreа оf seсtоr
= 25.66
→ Аreа оf seсtоr
≈ 26. (аррrоx.)
Henсe, the аreа оf seсtоr is 26сm², орtiоn (с) is соrreсt.