Question

The ratio between the neutrons present in carbon and silicon with respect to mass number of 12 and 28 respectively is

Answer 1

Hello Madhushri
The mass number of an element=N(no. of protons+P(no. of neutrons)
Mass no. of C=12
No. of protons=Atomic no.=6
No. of neutrons in carbon=12-6=6
Similarly
Mass no. of Si=28
No. of protons of Si=14
No. of neutrons in Si=28-14=14

Ratio of neutrons=6/14=3/7. Ans

Hope it helps.

Answer 2

Answer:

n=a-z

12-6=6. carbon

si

p=14

28-14=14

6:3=3:7