The ratio between the speeds of two trains is 7 : 8. if the second train runs 400 km in 4hours, then the speed of the first train is:
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Answered by
6
Hey there !
Solution:
Let the speed of two trains be x : y
=> x : y = 7 : 8
Now the Second train covers 400 km in 4 hours
=> Speed of Second Train ( y ) = 400 / 4 = 100 km/hr.
So we get,
=> x : 100 = 7 : 8
Product of means = Product of extremes
=> x * 8 = 100 * 7
=> 8 x = 700
=> x = 700 / 8
=> x = 87.5 km/hr.
Hence the speed of 1st train is 87.5 km/hr.
Hope my answer helped !
Answered by
0
Hello dear your answer
Let the speed of the train be x which is 7x and 8X
The second train covered 400km in 4 hours
Speed of the train (y) = 400/4( cancel it we get 100)
100km/hr
So we get
X= 100=7:8
Product of means= Product of extreme
X*8=100*7
8X=700
X= 700/8( by cancelling we get 87.5)
X=87.5km/HR
Their fore the speed of the first train is 87.5km/HR...
Thanks!!!
Let the speed of the train be x which is 7x and 8X
The second train covered 400km in 4 hours
Speed of the train (y) = 400/4( cancel it we get 100)
100km/hr
So we get
X= 100=7:8
Product of means= Product of extreme
X*8=100*7
8X=700
X= 700/8( by cancelling we get 87.5)
X=87.5km/HR
Their fore the speed of the first train is 87.5km/HR...
Thanks!!!
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